Functions
Mathematics · Cheatsheet

Functions

Chapter 4 · Topic 2 Exam

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Coverage
Mixed practice over function definition, domain/range, all families (rational/radical/modulus/piecewise), partial fractions, classification (one-to-one, even/odd), composition, inverses, transformations.
Format
18 questions across 4 sections (A: 5, B: 5, C: 4, D: 4 longer). Designed for ~60 min in one sitting; pause and resume any time.
Function test
Vertical line test (graph) ⇔ no two ordered pairs share an xx.
Natural domain rules
Combine: denominator 0\ne 0, radicand 0\ge 0 (even root), argument >0>0 (log).
Range from graph
Read yy-values reached. For shifted-vertex parabolas, range is bounded by the yy of the vertex.
Rational $\dfrac{ax+b}{cx+d}$
VA: x=d/cx=-d/c. HA: y=a/cy=a/c.
Radical
y=c+kax+by = c + k\sqrt{ax+b}
Domain: ax+b0ax+b\ge 0. Range starts at y=cy=c; goes up if k>0k>0, down if k<0k<0.
Modulus equation
A=b    A=±b|A| = b\;\Rightarrow\;A=\pm b
Modulus inequalities
Ab    bAb     and     Ab    Ab   or   Ab|A|\le b\;\Leftrightarrow\;-b\le A\le b\;\;\text{ and }\;\;|A|\ge b\;\Leftrightarrow\;A\le -b\;\text{ or }\;A\ge b
Partial fractions — cover-up
For distinct linear factors: cover (xri)(x-r_i) and substitute x=rix=r_i to read off AiA_i.
Even / odd tests
f(x)=f(x)  [even]      f(x)=f(x)  [odd]f(-x)=f(x)\;[\text{even}]\;\;\;f(-x)=-f(x)\;[\text{odd}]
One-to-one ⇒ inverse exists
If many-to-one, restrict the domain (e.g. one side of the parabola vertex) before inverting.
Composition
(fg)(x)=f(g(x))(f\circ g)(x) = f(g(x))
Find $f^{-1}$
Swap xx and yy, solve for yy. Geometric: reflect graph in y=xy=x. Domain/range swap.
Self-inverse
f1(x)=f(x)f^{-1}(x) = f(x)
Examples: 1/x1/x, axa-x, (xk)/(x1)(x-k)/(x-1) for certain kk.
Combined transform
y=af(b(xh))+ky = a\,f(b(x-h)) + k
aa vert stretch · bb horiz · hh right · kk up.
Reflections
f(x): x-axis;    f(x): y-axis-f(x):\text{ x-axis};\;\;f(-x):\text{ y-axis}
Reciprocal $1/f$
Zeros of ff ⇒ VAs of 1/f1/f. Min of ff ⇒ max of 1/f1/f.
$|f(x)|$ vs $f(|x|)$
f(x)|f(x)|: flip below-axis up. f(x)f(|x|): replace x<0x<0 part with mirror of x>0x>0 part.
Trap — sign inside bracket
f(xh)f(x-h) shifts RIGHT by hh (subtracting hh moves right). Always counter-intuitive.
Trap — extraneous solutions
Modulus equations: split into cases and CHECK in the original. Squaring or expanding can add false roots.
Trap — domain of composition
D(fg)D(f\circ g) = {xD(g):g(x)D(f)}\{x \in D(g) : g(x) \in D(f)\}. Don't just take D(g)D(g).